Fn= Fn-1 + Fn-2: a different perspective
The following observations were made when I set about to explore Fibonacci numbers. I made one mistake in my exploration. I assumed F0=1.

The exploration started with the well-known recurrence equation: Fn = Fn-1 + Fn-2 (for n ≥ 2).

The fibonacci numbers Fibn (Fn with F0=0 & F1=1) table look like this:
Fib0 Fib1 Fib2 Fib3 Fib4 Fib5 Fib6 Fib7 Fib8 Fib9 Fib10 Fib11
01123581321345589


The series Gn (Fn with F0=1 & F1=1), that I ended up exploring, looks like this:
   G0    G1    G2    G3    G4    G5    G6    G7    G8    G9    G10    G11
1123581321345589144


Observation 1: The relationship between Fibn and Gn is given by: Fibn = Gn+1 - Gn

  • Fib1 = 1 & Fib0 = 0
  • Fib2 = Fib1 + Fib0 = Fib1
  • Fib3 = Fib2 + Fib1 = Fib1 + Fib1
  • Fib4 = Fib3 + Fib2 = Fib1 + Fib1 + Fib1
  • Fib5 = Fib4 + Fib3 = Fib1 + Fib1 + Fib1 + Fib1 + Fib1
  • G1 = 1 & G0 = 1
  • G2 = G1 + G0
  • G3 = G2 + G1 = G1 + G0 + G1
  • G4 = G3 + G2 = G1 + G0 + G1 + G1 + G0
  • G5 = G4 + G3 = G1 + G0 + G1 + G1 + G0 + G1 + G0 + G1

Observation 2:
Given an integer n, let Rn be the number of ways n can be reduced (by repeated use of factors 1 or 2) down to 1 or 0. Let Pn be the set of such paths from n to 1 or 0
The following tables lists the number of ways for n (in {2, 3, 4, 5}) to be reduced to 1 or 0:
For n=5For n=4For n=3For n=2
P5
  • 5 →-1 4 →-1 3 →-1 2 →-1 1
  • 5 →-1 4 →-1 3 →-1 2 →-2 0
  • 5 →-1 4 →-1 3 →-2 1
  • 5 →-1 4 →-2 2 →-1 1
  • 5 →-1 4 →-2 2 →-2 0
  • 5 →-2 3 →-1 2 →-1 1
  • 5 →-2 3 →-1 2 →-2 0
  • 5 →-2 3 →-2 1
P4
  • 4 →-1 3 →-1 2 →-1 1
  • 4 →-1 3 →-1 2 →-2 0
  • 4 →-1 3 →-2 1
  • 4 →-2 2 →-1 1
  • 4 →-2 2 →-2 0
P3
  • 3 →-1 2 →-1 1
  • 3 →-1 2 →-2 0
  • 3 →-2 1
P2
  • 2 →-1 1
  • 2 →-2 0
  • Ways to reach 1 = 5
  • Ways to reach 0 = 3
  • Ways to reach 1 or 0 (R5) = 8
  • Ways to reach 1 = 3
  • Ways to reach 0 = 2
  • Ways to reach 1 or 0 (R4) = 5
  • Ways to reach 1 = 2
  • Ways to reach 0 = 1
  • Ways to reach 1 or 0 (R3 ) = 3
  • Ways to reach 1 = 1
  • Ways to reach 0 = 1
  • Ways to 1 or 0 (R2) = 2

Observation 3: Rn seems to be sum of Rn-1 and Rn-2 (with n ≥ 2 and R1 and R0 both taken to be 1).

Follows an informal reasoning to support the above observation. Suppose Rn is the number of ways 1 or 0 can be reached using reduction steps 1 or 2 and Rn-1 is the number of ways 1 or 0 can be reached similarly. Then to calculate Rn+1, since n is reachable from n+1 by only one possible path (a reduction step of 1) and n-2 is reachable by only one possible (a reduction step of 2), Rn+1 must be the total of Rn-1 and Rn.

Observation 4: The set Pn has exactly Pn-1 paths to reach 1 and Pn-2 paths to reach 0 (for n ≥ 2).

Observation 5: ∀ n . Rn = Gn (Gn = Fn = Fn-1+ Fn-2 n ≥ 2 with F0 = F1 = 1)




Using the above observations, Fibn can be considered as the number of ways a given integer n can be reduced (by steps of 1 or 0) to 1.